Keshav can row 60 km downstream and 36 km u | vedclass

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(D) Let the speed of the boat in still water be $x \ km/h$ and the speed of the current be $y \ km/h$.Downstream speed $= (x + y) \ km/h$.Upstream spe

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$1.2$

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(D) Let the speed of the boat in still water be $x \ km/h$ and the speed of the current be $y \ km/h$.Downstream speed $= (x + y) \ km/h$.Upstream speed $= (x - y) \ km/h$.According to the problem:For downstream: $\frac{60}{x + y} = 10 \Rightarrow x + y = 6$ $...(i)$For upstream: $\frac{36}{x - y} = 10 \Rightarrow x - y = 3.6$ $...(ii)$Adding equations $(i)$ and $(ii)$:$(x + y) + (x - y) = 6 + 3.6$$2x = 9.6 \Rightarrow x = 4.8 \ km/h$.Substituting $x = 4.8$ in equation $(i)$:$4.8 + y = 6 \Rightarrow y = 6 - 4.8 = 1.2 \ km/h$.Thus,the velocity of the current is $1.2 \ km/h$.

Keshav can row $60 \ km$ downstream and $36 \ km$ upstream,taking $10 \ h$ each time. What is the velocity of the current? (in $km/h$)

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