Larger number of oxidation states are exhibited by the actinoids than those by the lanthanoids,the main reason being

  • A
    Lesser energy difference between $5f$ and $6d$ than $4f$ and $5d$ orbitals
  • B
    More energy difference between $5f$ and $6d$ than between $4f$ and $5d$ orbitals
  • C
    More reactive nature of the actinoids than the lanthanoids
  • D
    $4f$ orbitals are more diffused than $5f$ orbitals

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Similar Questions

$(i) La(OH)_3$ is the least basic among lanthanide hydroxides. $(ii) Zr^{4+}$ and $Hf^{4+}$ have almost identical ionic radii. $(iii) Ce^{4+}$ can act as an oxidizing agent. Which of the above statements are correct?

Write a reaction with lanthanoids $(Ln)$:

Which of the following statements is $NOT$ incorrect?

Given below are two statements:
Statement $I$: In the Lanthanoids,the formation of $Ce^{+4}$ is favoured by its noble gas configuration.
Statement $II$: $Ce^{+4}$ is a strong oxidant reverting to the common $+3$ state.
In the light of the above statements,choose the most appropriate answer from the options given below:

Which pair of ions among the following can be separated by the precipitation method?

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