(B) Let $S = a + b + c + d + e$. The given system of equations can be written as:$S + a = 6$$S + b = 12$$S + c = 24$$S + d = 48$$S + e = 96$Summing th

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(B) Let $S = a + b + c + d + e$. The given system of equations can be written as:$S + a = 6$$S + b = 12$$S + c = 24$$S + d = 48$$S + e = 96$Summing these five equations,we get:$5S + (a + b + c + d + e) = 6 + 12 + 24 + 48 + 96$$5S + S = 186$$6S = 186$$S = 31$Now,substitute $S = 31$ into the third equation $S + c = 24$:$31 + c = 24$$c = 24 - 31 = -7$Therefore,$|c| = |-7| = 7$.

Competitive Quantitative Aptitude Algebra QUADRATIC EQUATION

Difficult

Let $a, b, c, d, e$ be five numbers satisfying the system of equations:
$2a + b + c + d + e = 6$
$a + 2b + c + d + e = 12$
$a + b + 2c + d + e = 24$
$a + b + c + 2d + e = 48$
$a + b + c + d + 2e = 96$
Then $|c|$ is equal to:

A
$6$
B
$7$
C
$8$
D
$25$

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Algebra

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QUADRATIC EQUATION

If $\sqrt {3x^2 - 7x - 30} + \sqrt {2x^2 - 7x - 5} = x + 5$, then $x$ is equal to

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If $a \in R$ and the equation $-3(x - [x])^2 + 2(x - [x]) + a^2 = 0$ (where $[x]$ denotes the greatest integer $\leq x$) has no integral solution,then all possible values of $a$ lie in the interval

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Solve the given two equations and select the correct answer from the given options.
$I.$ $\sqrt{x} - \frac{(18)^{15/2}}{x^2} = 0$
$II.$ $\sqrt{y} = \frac{(19)^{9/2}}{y}$

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Let $\alpha$ and $\beta$ be the roots of the quadratic equation $ax^2 + bx + c = 0$. If $a, b, c$ are in $A.P.$ and $\alpha + \beta = 15$,then $\alpha\beta$ equals:

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If $\alpha$ and $\beta$ are the roots of the equation $x^2 - 2x + 3 = 0$,then the equation whose roots are $\frac{1}{\alpha^2}$ and $\frac{1}{\beta^2}$ is:

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Let $a, b, c, d, e$ be five numbers satisfying the system of equations:$2a + b + c + d + e = 6$$a + 2b + c + d + e = 12$$a + b + 2c + d + e = 24$$a + b + c + 2d + e = 48$$a + b + c + d + 2e = 96$Then $|c|$ is equal to:

Similar Questions

If $\sqrt {3x^2 - 7x - 30} + \sqrt {2x^2 - 7x - 5} = x + 5$, then $x$ is equal to

If $a \in R$ and the equation $-3(x - [x])^2 + 2(x - [x]) + a^2 = 0$ (where $[x]$ denotes the greatest integer $\leq x$) has no integral solution,then all possible values of $a$ lie in the interval

Solve the given two equations and select the correct answer from the given options.$I.$ $\sqrt{x} - \frac{(18)^{15/2}}{x^2} = 0$$II.$ $\sqrt{y} = \frac{(19)^{9/2}}{y}$

Let $\alpha$ and $\beta$ be the roots of the quadratic equation $ax^2 + bx + c = 0$. If $a, b, c$ are in $A.P.$ and $\alpha + \beta = 15$,then $\alpha\beta$ equals:

If $\alpha$ and $\beta$ are the roots of the equation $x^2 - 2x + 3 = 0$,then the equation whose roots are $\frac{1}{\alpha^2}$ and $\frac{1}{\beta^2}$ is:

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Let $a, b, c, d, e$ be five numbers satisfying the system of equations:
$2a + b + c + d + e = 6$
$a + 2b + c + d + e = 12$
$a + b + 2c + d + e = 24$
$a + b + c + 2d + e = 48$
$a + b + c + d + 2e = 96$
Then $|c|$ is equal to:

Solve the given two equations and select the correct answer from the given options.
$I.$ $\sqrt{x} - \frac{(18)^{15/2}}{x^2} = 0$
$II.$ $\sqrt{y} = \frac{(19)^{9/2}}{y}$