Let $A = \{1, 2, 3, 4\}$ and $R$ be a relation on the set $A \times A$ defined by $R = \{((a, b), (c, d)) : 2a + 3b = 4c + 5d\}$. Then the number of elements in $R$ is:

  • A
    $6$
  • B
    $5$
  • C
    $4$
  • D
    $3$

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