Let $y=y(x)$ be the solution of the differential equation $(x^2+4)^2 dy + (2x^3y+8xy-2) dx = 0$. If $y(0)=0$,then $y(2)$ is equal to

  • A
    $\frac{\pi}{8}$
  • B
    $\frac{\pi}{16}$
  • C
    $2\pi$
  • D
    $\frac{\pi}{32}$

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