Let n geq 2 be an integer. Take n distinct po | vedclass

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(C) The total number of line segments formed by joining $n$ points is given by $\binom{n}{2} = \frac{n(n-1)}{2}$.The number of line segments joining a

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$5$

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(C) The total number of line segments formed by joining $n$ points is given by $\binom{n}{2} = \frac{n(n-1)}{2}$.The number of line segments joining adjacent points (which form the sides of an $n$-sided polygon) is $n$.The number of line segments joining non-adjacent points (which are the diagonals of the polygon) is $\binom{n}{2} - n$.According to the problem,the number of blue segments (adjacent) equals the number of red segments (non-adjacent):$n = \binom{n}{2} - n$$2n = \frac{n(n-1)}{2}$$4n = n^2 - n$$n^2 - 5n = 0$$n(n - 5) = 0$Since $n \geq 2$,we have $n = 5$.

Let $n \geq 2$ be an integer. Take $n$ distinct points on a circle and join each pair of points by a line segment. Colour the line segment joining every pair of adjacent points blue and the rest red. If the number of red and blue line segments are equal,then the value of $n$ is

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