Let $f(x)=5-|x-2|$ and $g(x)=|x+1|, x \in R$. If $f(x)$ attains its maximum value at $\alpha$ and $g(x)$ attains its minimum value at $\beta$,then $\lim _{x \rightarrow-\alpha \beta} \frac{(x-1)\left(x^2-5 x+6\right)}{x^2-6 x+8}$ is equal to

  • A
    $\frac{1}{2}$
  • B
    $\frac{-3}{2}$
  • C
    $\frac{-1}{2}$
  • D
    $\frac{3}{2}$

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