Let A = {a, b, c, d} and B = {1, 2, 3}. The r | vedclass

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(D) relation $f$ from set $A$ to set $B$ is a function if every element of $A$ has a unique image in $B$.For $R_1$: Each element of $A$ has exactly on

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Only $R_4$ is not a function

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(D) relation $f$ from set $A$ to set $B$ is a function if every element of $A$ has a unique image in $B$.For $R_1$: Each element of $A$ has exactly one image in $B$. Thus,$R_1$ is a function.For $R_2$: Each element of $A$ has exactly one image in $B$. Thus,$R_2$ is a function.For $R_3$: Each element of $A$ has exactly one image in $B$. Thus,$R_3$ is a function.For $R_4$: The element $a \in A$ is mapped to two different values,$1$ and $2$ (i.e.,$(a, 1) \in R_4$ and $(a, 2) \in R_4$).Since an element cannot have two distinct images,$R_4$ is not a function.Therefore,only $R_4$ is not a function.

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