Let $\sigma_1$ and $\sigma_2$ be the standard deviations of two distributions $D_1$ and $D_2$ respectively,and $D_1$ be more consistent than $D_2$. If the means of $D_1$ and $D_2$ are the same,then the percentage increase in the standard deviation of $D_2$ over the standard deviation of $D_1$ is:

  • A
    $\frac{\sigma_1-\sigma_2}{\sigma_2} \times 100$
  • B
    $\frac{\sigma_1-\sigma_2}{\sigma_1} \times 100$
  • C
    $\frac{\sigma_2-\sigma_1}{\sigma_2} \times 100$
  • D
    $\frac{\sigma_2-\sigma_1}{\sigma_1} \times 100$

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If the standard deviation of the numbers $2, 3, 2x$,and $11$ is $3.5$,find the possible values of $x$.

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The variance of the following frequency distribution is:
Class Interval$0$-$4$$4$-$8$$8$-$12$$12$-$16$$16$-$20$
Frequency$2$$4$$6$$3$$1$

Calculate the mean,variance,and standard deviation for the following distribution:
Class $30-40$ $40-50$ $50-60$ $60-70$ $70-80$ $80-90$ $90-100$
$f_i$ $3$ $7$ $12$ $15$ $8$ $3$ $2$

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Statement-$1$: The variance of the first $n$ even natural numbers is $\frac{n^2 - 1}{4}$.
Statement-$2$: The sum of the first $n$ natural numbers is $\frac{n(n + 1)}{2}$ and the sum of the squares of the first $n$ natural numbers is $\frac{n(n + 1)(2n + 1)}{6}$.

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