Let $g(x) = 1 + x - [x]$ and $f(x) = \begin{cases} -1, & x < 0 \\ 0, & x = 0 \\ 1, & x > 0 \end{cases}$. Then for all $x$,$f(g(x))$ is equal to

  • A
    $x$
  • B
    $1$
  • C
    $f(x)$
  • D
    $g(x)$

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