Let a line $L$ be perpendicular to both the lines $L_1: \frac{x+1}{3} = \frac{y+3}{5} = \frac{z+5}{7}$ and $L_2: \frac{x-2}{1} = \frac{y-4}{4} = \frac{z-6}{7}$. If $\theta$ is the acute angle between the lines $L$ and $L_3: \frac{x-7}{2} = \frac{y-7}{1} = \frac{z}{2}$, then $\tan \theta$ is equal to:

  • A
    $\frac{3}{2}\sqrt{2}$
  • B
    $\frac{5}{2}\sqrt{2}$
  • C
    $\frac{5}{3}\sqrt{2}$
  • D
    $\frac{4}{3}\sqrt{2}$

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