Let the speed of light in a medium be V and t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) According to Brewster's Law,the refractive index $\mu$ of a medium is given by $\mu = 	an(i_p)$,where $i_p$ is the polarising angle.Also,the refr

Vedclass · Accepted Answer

$V \sin(i_p) = C \cos(i_p)$

Vedclass · Answer

(D) According to Brewster's Law,the refractive index $\mu$ of a medium is given by $\mu = 	an(i_p)$,where $i_p$ is the polarising angle.Also,the refractive index $\mu$ is defined as the ratio of the speed of light in vacuum $(C)$ to the speed of light in the medium $(V)$: $\mu = \frac{C}{V}$.Equating the two expressions for $\mu$,we get: $\frac{C}{V} = 	an(i_p)$.This can be written as $\frac{C}{V} = \frac{\sin(i_p)}{\cos(i_p)}$.Rearranging the terms,we get $C \cos(i_p) = V \sin(i_p)$,which is equivalent to $V \sin(i_p) = C \cos(i_p)$.

Let the speed of light in a medium be $V$ and the polarising angle be $i_p$. If $C$ is the speed of light in vacuum,what is the relation between them?

Similar Questions

The angle of polarisation for any medium is $60^{\circ}$. What will be the critical angle for this medium?

Unpolarized light of intensity $I_0$ is incident on the surface of a block of glass at Brewster's angle. In that case,which one of the following statements is true?

The Brewster angle for air to glass transition of light is (Refractive index of glass $= 1.5$).

$A$ ray of light is incident on the surface of a glass plate of refractive index $\sqrt{3}$ at the polarising angle. The angle of refraction of the ray is (in $^{\circ}$)

The critical angle of a certain medium is ${\sin ^{ - 1}}\left( {\frac{3}{5}} \right)$. The polarization angle is

Vedclass Test Series

Exam Paper Generator

Online Exam Module