Light of wavelength 550, nm falls normally on | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) For single slit diffraction,the condition for the $n^{th}$ minima is given by $a \sin 	heta = n\lambda$,where $a$ is the slit width,$\lambda$ is

Vedclass · Accepted Answer

$\frac{\pi}{6}$

Vedclass · Answer

(D) For single slit diffraction,the condition for the $n^{th}$ minima is given by $a \sin 	heta = n\lambda$,where $a$ is the slit width,$\lambda$ is the wavelength,and $	heta$ is the angular position.Given: $\lambda = 550\, nm = 550 	imes 10^{-9}\, m$,$a = 22.0 	imes 10^{-5}\, cm = 22.0 	imes 10^{-7}\, m$,and $n = 2$ for the second minima.Substituting the values into the formula:$a \sin 	heta = 2\lambda$$\sin 	heta = \frac{2\lambda}{a} = \frac{2 	imes 550 	imes 10^{-9}}{22.0 	imes 10^{-7}}$$\sin 	heta = \frac{1100 	imes 10^{-9}}{22.0 	imes 10^{-7}} = \frac{1100}{2200} = 0.5$Since $\sin 	heta = 0.5$,we have $	heta = \arcsin(0.5) = \frac{\pi}{6}\, rad$.

Light of wavelength $550\, nm$ falls normally on a slit of width $22.0 \times 10^{-5}\, cm$. The angular position of the second minima from the central maximum will be (in radians)

Similar Questions

Which scientist discovered the phenomenon of diffraction of light?

In a single-slit diffraction pattern,the intensity of the central maximum is $I_0$. If the slit width is doubled,what will be the intensity of the central maximum?

If the measured angular separation between the second minimum to the left of the central maximum and the third minimum to the right of the central maximum is $30^{\circ}$ in a single slit diffraction pattern recorded using $628 \ nm$ light,then the width of the slit is . . . . . . $\mu m$.

In a single-slit diffraction experiment, the slit is illuminated by light of two wavelengths $\lambda_1$ and $\lambda_2$. It is observed that the $2^{nd}$ order diffraction minimum for $\lambda_1$ coincides with the $3^{rd}$ diffraction minimum for $\lambda_2$. Then:

The angular spread of the central maximum in a diffraction pattern does not depend on . . . . . . .

Vedclass Test Series

Exam Paper Generator

Online Exam Module