Light of wavelength 300 nm in medium A enter | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The speed of light in medium $A$ is given by $v_A = f \lambda_A = (5 	imes 10^{14} \ Hz) 	imes (300 	imes 10^{-9} \ m) = 1.5 	imes 10^8 \ m/s$

Vedclass · Accepted Answer

$1.6$

Vedclass · Answer

(A) The speed of light in medium $A$ is given by $v_A = f \lambda_A = (5 	imes 10^{14} \ Hz) 	imes (300 	imes 10^{-9} \ m) = 1.5 	imes 10^8 \ m/s$. The absolute refractive index of medium $A$ is $\mu_A = \frac{c}{v_A} = \frac{3 	imes 10^8 \ m/s}{1.5 	imes 10^8 \ m/s} = 2$. We are given the ratio of speeds $\frac{v_A}{v_B} = \frac{4}{5}$. Since the refractive index $\mu$ is inversely proportional to the speed of light $v$ $(\mu = \frac{c}{v})$,we have $\frac{\mu_B}{\mu_A} = \frac{v_A}{v_B}$. Substituting the values: $\frac{\mu_B}{2} = \frac{4}{5}$. Therefore,$\mu_B = 2 	imes \frac{4}{5} = \frac{8}{5} = 1.6$.

Light of wavelength $300 \ nm$ in medium $A$ enters into medium $B$ through a plane surface. If the frequency of light is $5 \times 10^{14} \ Hz$ and the ratio of speed in medium $A$ to that in medium $B$ is $\frac{4}{5}$,the absolute refractive index of medium $B$ is:

Similar Questions

$A$ fish rising vertically at the rate of $3 \, m/s$ to the surface of water observes a bird above the water,diving vertically towards it at the rate of $9 \, m/s$. The refractive index of water is $4/3$. Calculate the actual velocity (velocity $w.r.t$ ground) of the bird in $m/s$.

Refractive index of a medium is $\mu$. If the angle of incidence is twice that of the angle of refraction, then the angle of incidence is

In the figure below,$PQRS$ denotes the path followed by a ray of light as it travels through three media in succession. The absolute refractive indices of the media are $\mu_1, \mu_2$ and $\mu_3$,respectively. (The line segment $RS$ in the figure is parallel to $PQ$). Then,

$A$ red colour in air has a wavelength of $760 \,nm$. When light passes through water of refractive index $n = \frac{4}{3}$,its wavelength becomes $570 \,nm$. (The wavelength of yellow colour in air is $570 \,nm$). The colour of the red light in water is:

$A$ light ray of frequency '$v$' and wavelength '$\lambda$' enters a liquid of refractive index $\frac{3}{2}$. The ray travels in the liquid with:

Vedclass Test Series

Exam Paper Generator

Online Exam Module