Limiting molar conductivity of Mg^{2+} and Cl | vedclass

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(B) According to Kohlrausch's law of independent migration of ions,the limiting molar conductivity of an electrolyte is the sum of the limiting molar

Vedclass · Accepted Answer

$258.6$

Vedclass · Answer

(B) According to Kohlrausch's law of independent migration of ions,the limiting molar conductivity of an electrolyte is the sum of the limiting molar conductivities of its constituent ions. For $MgCl_2$,the dissociation is $MgCl_2 ightarrow Mg^{2+} + 2Cl^{-}$. Therefore,$\Lambda^{\circ}_{m(MgCl_2)} = \Lambda^{\circ}_{m(Mg^{2+})} + 2 	imes \Lambda^{\circ}_{m(Cl^{-})}$. Given: $\Lambda^{\circ}_{m(Mg^{2+})} = 106.0 \ S \ cm^2 \ mol^{-1}$ and $\Lambda^{\circ}_{m(Cl^{-})} = 76.3 \ S \ cm^2 \ mol^{-1}$. $\Lambda^{\circ}_{m(MgCl_2)} = 106.0 + 2 	imes 76.3 = 106.0 + 152.6 = 258.6 \ S \ cm^2 \ mol^{-1}$.

Limiting molar conductivity of $Mg^{2+}$ and $Cl^{-}$ ions in water is $106.0 \ S \ cm^2 \ mol^{-1}$ and $76.3 \ S \ cm^2 \ mol^{-1}$ respectively. The limiting molar conductivity of magnesium chloride (in $S \ cm^2 \ mol^{-1}$) in water is

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