Magnesium reacts with an element (X) to form | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The electronic configuration of element $(X)$ is $1s^{2} 2s^{2} 2p^{3}$.This corresponds to Nitrogen $(N)$,which has $5$ valence electrons and nee

Vedclass · Accepted Answer

$Mg_{3}X_{2}$

Vedclass · Answer

(D) The electronic configuration of element $(X)$ is $1s^{2} 2s^{2} 2p^{3}$.This corresponds to Nitrogen $(N)$,which has $5$ valence electrons and needs $3$ electrons to complete its octet,forming an ion with a charge of $-3$ $(N^{3-})$.Magnesium $(Mg)$ is an alkaline earth metal with $2$ valence electrons,forming an ion with a charge of $+2$ $(Mg^{2+})$.To form a neutral ionic compound,the charges must balance: $3 	imes (+2) + 2 	imes (-3) = 0$.Therefore,the simplest formula for the compound is $Mg_{3}X_{2}$.

Magnesium reacts with an element $(X)$ to form an ionic compound. If the ground state electronic configuration of $(X)$ is $1s^{2} 2s^{2} 2p^{3},$ the simplest formula for this compound is

Similar Questions

$CsBr_3$ contains

Ionic compounds are formed most easily with

Assertion $(A)$: Higher lattice enthalpy leads to greater stability of ionic compounds.
Reason $(R)$: Lattice enthalpy is a direct measure of the electrostatic forces of repulsion among the constituent ions in an ionic solid.
The correct answer is

Find out the correct order of ionic character in the following molecules:
$(i)$ $O_2$
$(ii)$ $K_2O$
$(iii)$ $N_2$
$(iv)$ $LiF$

Out of the following,which compound will have electrovalent bonding?

Vedclass Test Series

Exam Paper Generator

Online Exam Module