Magnetic flux linked with the coil is given by $\phi(t) = 2t^2 + 2t + 1$ and its resistance is $10 \ \Omega$. The current passing through the coil at $t = 2 \ s$ is . . . . . . $A$.

If we move a magnet towards a coil,keeping the $N$ pole in front of the coil,then that side of the coil behaves as which pole?

$A$ loop of irregular shape of conducting wire (as shown in the figure) is placed in a uniform magnetic field perpendicular to the plane of the paper. If the loop changes into a circular shape,the direction of the induced current will be:

Assertion $(A):$ The bar magnet falling vertically along the axis of the horizontal coil will have an acceleration less than $g$.
Reason $(R):$ Clockwise current is induced in the coil.

$A$ $10 \Omega$ coil of $180$ turns and diameter $4 \text{ cm}$ is placed in a uniform magnetic field so that the magnetic flux is maximum through the coil's cross-sectional area. When the field is suddenly removed, a charge of $360 \mu \text{C}$ flows through a $618 \Omega$ galvanometer connected to the coil. Find the magnetic field. (in $\text{ T}$)

$A$ bar magnet is passing through a conducting loop of radius $R$ with velocity $v$. The radius of the bar magnet is such that it just passes through the loop. The induced $e.m.f.$ in the loop can be represented by the approximate curve: