Magnetic induction at the centre of a circula | vedclass

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Question

(B) The magnetic induction $B$ at the centre of a circular loop is given by $B = \frac{\mu_0 i}{2r}$.Given area $A = \pi \ m^2$,so $\pi r^2 = \pi$,whi

Vedclass · Accepted Answer

$\frac{0.2 \pi}{\mu_0}$

Vedclass · Answer

(B) The magnetic induction $B$ at the centre of a circular loop is given by $B = \frac{\mu_0 i}{2r}$.Given area $A = \pi \ m^2$,so $\pi r^2 = \pi$,which implies $r = 1 \ m$.From the formula $B = \frac{\mu_0 i}{2r}$,we have $i = \frac{2Br}{\mu_0}$.The magnetic moment $M$ is given by $M = iA$.Substituting the values: $M = \left( \frac{2Br}{\mu_0} ight) A$.$M = \frac{2 	imes 0.1 	imes 1 	imes \pi}{\mu_0} = \frac{0.2 \pi}{\mu_0} \ A \cdot m^2$.

Magnetic induction at the centre of a circular loop of area $\pi \ m^2$ is $0.1 \ T$. The magnetic moment of the loop is ( $\mu_0 = \text{permeability of air}$ ).

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