What is the major product of the following re | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction of $1,3$-butadiene with $1 	ext{ eq}$ of $Br_2$ at high temperature (indicated by $\Delta$) is a thermodynamic control reaction. In

Vedclass · Accepted Answer

$1,4-$dibromobut$-2-$ene

Vedclass · Answer

(B) The reaction of $1,3$-butadiene with $1 	ext{ eq}$ of $Br_2$ at high temperature (indicated by $\Delta$) is a thermodynamic control reaction. In thermodynamic control,the more stable product is formed. $1,3$-butadiene reacts with $Br_2$ to form a carbocation intermediate. Electrophilic addition of $Br_2$ to $1,3$-butadiene can occur at the $1,2$-position or the $1,4$-position. The $1,4$-addition product,$1,4$-dibromobut-$2$-ene,is more stable than the $1,2$-addition product,$3,4$-dibromobut-$1$-ene,because the double bond in the $1,4$-product is disubstituted,whereas the double bond in the $1,2$-product is monosubstituted. Therefore,at higher temperatures,the $1,4$-addition product is the major product.

What is the major product of the following reaction?
$CH_2=CH-CH=CH_2 + Br_2 \text{ (1 eq)} \xrightarrow{\Delta} ?$

Similar Questions

$[CH_3-CH_2-CH(CH_3)-N^{+}(CH_3)_3]OH^{-} \xrightarrow{\text{pyrolysis}}$ major alkene will be

What is meant by hydroboration-oxidation reaction? Illustrate it with an example.

Write in detail about the hydrogenation of unsaturated hydrocarbons.

Predict the product$(s)$ obtained for the following reaction:
$3$-methylcyclopentene + $Br_2 / CCl_4 \rightarrow ?$

The compounds that will give an isomer of $2,2$-dimethylpropane on catalytic hydrogenation are:
$(1)$ $CH_3-CH=C(CH_3)_2$
$(2)$ $CH_3-CH=CH-CH_3$
$(3)$ $CH_3-CH=CH-CH_2-CH_3$
$(4)$ $CH_3-C(CH_3)=C(CH_3)-CH_3$

Vedclass Test Series

Exam Paper Generator

Online Exam Module

What is the major product of the following reaction? $CH_2=CH-CH=CH_2 + Br_2 \text{ (1 eq)} \xrightarrow{\Delta} ?$