The major product of the following reaction i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The reaction involves the electrophilic addition of $HBr$ to the two double bonds present in the molecule,which is allyl acrylate $(CH_2=CH-COO-CH

Vedclass · Accepted Answer

$1-$bromopropan$-2-$yl $3-$bromopropanoate

Vedclass · Answer

(D) The reaction involves the electrophilic addition of $HBr$ to the two double bonds present in the molecule,which is allyl acrylate $(CH_2=CH-COO-CH_2-CH=CH_2)$.$1$. The first $HBr$ molecule adds to the more reactive double bond. The double bond in the allyl group (alkene part) is more electron-rich than the double bond conjugated with the carbonyl group (acrylate part). Thus,$HBr$ adds to the allyl double bond following Markovnikov's rule to form $CH_2=CH-COO-CH_2-CH(Br)-CH_3$.$2$. The second $HBr$ molecule adds to the remaining double bond in the acrylate part. This addition follows anti-Markovnikov's rule (if peroxide is present,though usually,in the absence of peroxide,it follows Markovnikov's rule,but here the electron-withdrawing carbonyl group directs the addition to the terminal carbon to form the more stable carbocation or via conjugate addition). The addition to the $CH_2=CH-$ group results in the formation of $Br-CH_2-CH_2-COO-CH_2-CH(Br)-CH_3$.Therefore,the final product is $1-$bromopropan$-2-$yl $3-$bromopropanoate.

The major product of the following reaction is:

Similar Questions

The product of the reaction between propene and $HBr$ in the presence of a peroxide is:

Which of the following is the most stable?

Identify $A$ in the reaction:

Which hydrogen halide adds to propene in the presence of peroxide following the anti-Markovnikov rule?

Select the suitable reagent for the conversion shown below:

Vedclass Test Series

Exam Paper Generator

Online Exam Module