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Write the main product of the given reactions:
$1$. $(CH_3)_2CHCHBrCH_3 \xrightarrow[ethanol]{KOH, \Delta }$
$2$. $(CH_3)_2CHCH(OH)CH_3 \xrightarrow{H_2SO_4, \Delta }$

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The boiling point of methanol $(CH_3OH)$ is higher than that of methyl thiol $(CH_3SH)$ because:

$1-$Propanol can be distinguished from $2-$propanol by which test?

Which of the following is the correct decreasing order of water solubility for the given organic compounds?

$HO-CH_2CH_2CH_2CH_2-Br \xrightarrow{KOH} \text{Product}$. The product is:

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