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(C) The reaction of $t$-butyl methyl ether with $HI$ proceeds via an $S_N1$ mechanism.$1$. The oxygen atom of the ether is protonated by $HI$ to form

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$(CH_3)_3CI$ and $CH_3OH$

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(C) The reaction of $t$-butyl methyl ether with $HI$ proceeds via an $S_N1$ mechanism.$1$. The oxygen atom of the ether is protonated by $HI$ to form an oxonium ion.$2$. The $C-O$ bond between the $t$-butyl group and the oxygen atom breaks to form a stable $t$-butyl carbocation $(CH_3)_3C^+$ and methanol $(CH_3OH)$.$3$. The iodide ion $(I^-)$ then attacks the $t$-butyl carbocation to form $t$-butyl iodide $(CH_3)_3CI$.Thus,the major products are $t$-butyl iodide and methanol.

The major products formed in the reaction of $t$-butyl methyl ether with $HI$ are

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