Mark the correct match.

  • A
    Catalytic $RNA$ in bacteria - $16S$ $rRNA$ and $23S$ $rRNA$ as ribozyme.
  • B
    $Val$ operon - Found in eukaryotes.
  • C
    Sanger method - Determination of amino acid sequences in proteins only.
  • D
    $VNTR$ - Intron.

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Similar Questions

Match the following columns:
Column-$I$ Column-$II$
$(a)$ Exon $(I)$ Non-coding sequence
$(b)$ Intron $(II)$ Coding sequence
$(c)$ Genetic code $(III)$ Nucleosome
$(d)$ $DNA$ packaging $(IV)$ Nirenberg,Khorana and Matthaei

Read the following statements $:-$
$(i)$ Eukaryotic $\text{mRNA}$ is polycistronic whereas prokaryotic $\text{mRNA}$ is monocistronic.
$(ii)$ Prokaryotic $\text{mRNA}$ is cap-less and tail-less whereas eukaryotic $\text{mRNA}$ is with cap and tail.
$(iii)$ The precursor of prokaryotic $\text{mRNA}$ is $\text{hnRNA}$.
$(iv)$ In replication,only one of the strands acts as a template.
$(v)$ In eukaryotes,transcription occurs in the nucleus and translation in the cytoplasm.
Which of the above statements are correct?

Difficult
View Solution

Match the following columns:
Column-$I$Column-$II$
$(W)$ Griffith$(1)$ $DNA$ is the genetic material
$(X)$ Avery,MacLeod$(2)$ Semiconservative replication
$(Y)$ Meselson-Stahl$(3)$ Transforming principle
$(Z)$ Hershey and Chase$(4)$ Transformation inhibited by $DNase$

The one-gene-one-enzyme relationship was first established in.....

Match the following in column $I$ with column $II$ and choose the correct combination.
Column $I$ Column $II$
$a.$ Termination $i.$ Aminoacyl $t-RNA$ synthetase
$b.$ Translation $ii.$ Okazaki fragments
$c.$ Transcription $iii.$ $GTP$ dependent release factor
$d.$ $DNA$ replication $iv.$ $RNA$ polymerase

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