Match Column-$I$ with Column-$II$ for the given properties/applications mentioned therein.
Column-$I$ Column-$II$ $A$. $H$ $1$. Used in the name of perhydrol. $B$. $H_2$ $2$. Can be reduced to dihydrogen by $NaH$. $C$. $H_2O$ $3$. Can be used in hydroformylation of olefin. $D$. $H_2O_2$ $4$. Can be used in cutting and welding.
| Column-$I$ | Column-$II$ |
| $A$. $H$ | $1$. Used in the name of perhydrol. |
| $B$. $H_2$ | $2$. Can be reduced to dihydrogen by $NaH$. |
| $C$. $H_2O$ | $3$. Can be used in hydroformylation of olefin. |
| $D$. $H_2O_2$ | $4$. Can be used in cutting and welding. |
(A-4, B-3, C-2, D-1) The correct matches are:
$A-4$: Atomic hydrogen $(H)$ is used in atomic hydrogen welding and cutting.
$B-3$: Dihydrogen $(H_2)$ is used in the hydroformylation of olefins to produce aldehydes.
$C-2$: Water $(H_2O)$ can be reduced to dihydrogen by $NaH$ $(NaH + H_2O \rightarrow NaOH + H_2)$.
$D-1$: Hydrogen peroxide $(H_2O_2)$ is known as perhydrol.
Therefore,the correct sequence is $A-4, B-3, C-2, D-1$.
$A-4$: Atomic hydrogen $(H)$ is used in atomic hydrogen welding and cutting.
$B-3$: Dihydrogen $(H_2)$ is used in the hydroformylation of olefins to produce aldehydes.
$C-2$: Water $(H_2O)$ can be reduced to dihydrogen by $NaH$ $(NaH + H_2O \rightarrow NaOH + H_2)$.
$D-1$: Hydrogen peroxide $(H_2O_2)$ is known as perhydrol.
Therefore,the correct sequence is $A-4, B-3, C-2, D-1$.
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Similar Questions
When oxalic acid reacts with conc. $H_2SO_4$,two gases produced are of neutral and acidic in nature respectively. Potassium hydroxide absorbs one of the two gases. The product formed during this absorption and the gas which gets absorbed are respectively
Medium
View Solution$H_2C_2O_4 \xrightarrow{\Delta } \text{gas } (A) + \text{gas } (B) + \text{liquid } (C)$.
$\text{Gas } (A) \text{ burns with a blue flame and is oxidised to gas } (B)$.
$\text{Gas } (A) + Cl_2 \to (D) \xrightarrow{NH_3, \Delta } (E)$.
$A, B, C \text{ and } E \text{ are}$
$\text{Gas } (A) \text{ burns with a blue flame and is oxidised to gas } (B)$.
$\text{Gas } (A) + Cl_2 \to (D) \xrightarrow{NH_3, \Delta } (E)$.
$A, B, C \text{ and } E \text{ are}$
Match the terms in Column $-I$ with the relevant item in Column $-II$.
Column $-I$ Column $-II$ $A$. Electrolysis of water produces $1$. atomic reactor $B$. Lithium aluminium hydride is used as $2$. polar molecule $C$. Hydrogen chloride is a $3$. recombines on metal surface to generate high temperature $D$. Heavy water is used in $4$. reducing agent $E$. Atomic hydrogen $5$. hydrogen and oxygen
| Column $-I$ | Column $-II$ |
| $A$. Electrolysis of water produces | $1$. atomic reactor |
| $B$. Lithium aluminium hydride is used as | $2$. polar molecule |
| $C$. Hydrogen chloride is a | $3$. recombines on metal surface to generate high temperature |
| $D$. Heavy water is used in | $4$. reducing agent |
| $E$. Atomic hydrogen | $5$. hydrogen and oxygen |
Difficult
View SolutionOxalic acid reacts with concentrated $H_2SO_4$ to produce a mixture of two gases. When this mixture is passed through caustic potash,one of the gases is absorbed. Which substance is formed by the absorption of the gas in caustic potash?
Medium
View SolutionMatch the following columns:
Column-$I$ Column-$II$ $(i)$ Hydrogen peroxide $(a)$ Used as air purifier in submarines $(ii)$ Calcium sulphate hemihydrate $(b)$ Used for water softening $(iii)$ Potassium superoxide $(c)$ Antiseptic $(iv)$ Calgon $(d)$ Plaster of Paris
| Column-$I$ | Column-$II$ |
| $(i)$ Hydrogen peroxide | $(a)$ Used as air purifier in submarines |
| $(ii)$ Calcium sulphate hemihydrate | $(b)$ Used for water softening |
| $(iii)$ Potassium superoxide | $(c)$ Antiseptic |
| $(iv)$ Calgon | $(d)$ Plaster of Paris |
Medium
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