Match List-I with List-II:List-I (Pair of Com | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) . $n$-propanol $(CH_3CH_2CH_2OH)$ and Isopropanol $(CH_3CH(OH)CH_3)$ differ in the position of the $-OH$ group,hence they are Position isomers $(I

Vedclass · Accepted Answer

$A-III, B-I, C-IV, D-II$

Vedclass · Answer

(D) . $n$-propanol $(CH_3CH_2CH_2OH)$ and Isopropanol $(CH_3CH(OH)CH_3)$ differ in the position of the $-OH$ group,hence they are Position isomers $(III)$.$B$. Methoxypropane $(CH_3OCH_2CH_2CH_3)$ and ethoxyethane $(CH_3CH_2OCH_2CH_3)$ have different alkyl groups attached to the same functional group $(-O-)$,hence they are Metamers $(I)$.$C$. Propanone $(CH_3COCH_3)$ and propanal $(CH_3CH_2CHO)$ have different functional groups (ketone vs aldehyde),hence they are Functional isomers $(IV)$.$D$. Neopentane $(C(CH_3)_4)$ and Isopentane $(CH_3CH(CH_3)CH_2CH_3)$ differ in the arrangement of the carbon chain,hence they are Chain isomers $(II)$.Therefore,the correct matching is $A-III, B-I, C-IV, D-II$.

List-$I$ (Pair of Compounds)	List-$II$ (Isomerism)
$A$. $n$-propanol and Isopropanol	$(I)$ Metamerism
$B$. Methoxypropane and ethoxyethane	$(II)$ Chain Isomerism
$C$. Propanone and propanal	$(III)$ Position Isomerism
$D$. Neopentane and Isopentane	$(IV)$ Functional Isomerism

Similar Questions

Which one of the following pairs represents stereoisomerism?

Examine the following three pairs of possible isomers. Now state whether the pairs represent identical compounds or different isomers.

Compare the basic strengths of the given compounds:

Which of the following types of isomerism is shown by pentanone?

The circle represents the most basic atom in these molecules. Which of the following is the correct representation?

Vedclass Test Series

Exam Paper Generator

Online Exam Module