Match List I with List II and select the corr | vedclass

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Question

(A) Peroxide is $H_2O_2$,where oxygen is in $-1$ oxidation state.$(B)$ Superoxide is $KO_2$,where oxygen is in $-1/2$ oxidation state.$(C)$ Dioxide is

Vedclass · Accepted Answer

$A-4, B-3, C-2, D-1$

Vedclass · Answer

(A) Peroxide is $H_2O_2$,where oxygen is in $-1$ oxidation state.$(B)$ Superoxide is $KO_2$,where oxygen is in $-1/2$ oxidation state.$(C)$ Dioxide is $PbO_2$,where oxygen is in $-2$ oxidation state.$(D)$ Suboxide is $C_3O_2$,which contains less oxygen than expected from normal valency.Therefore,the correct match is $A-4, B-3, C-2, D-1$.

$A$. Peroxide	$1$. $C_3O_2$
$B$. Superoxide	$2$. $PbO_2$
$C$. Dioxide	$3$. $KO_2$
$D$. Suboxide	$4$. $H_2O_2$

Match List $I$ with List $II$ and select the correct answer using the codes given below the lists:
$A$. Peroxide $1$. $C_3O_2$
$B$. Superoxide $2$. $PbO_2$
$C$. Dioxide $3$. $KO_2$
$D$. Suboxide $4$. $H_2O_2$

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Match List $I$ with List $II$ and select the correct answer using the codes given below the lists:$A$. Peroxide$1$. $C_3O_2$$B$. Superoxide$2$. $PbO_2$$C$. Dioxide$3$. $KO_2$$D$. Suboxide$4$. $H_2O_2$