(C) . Hoffmann Bromamide Degradation uses $Br_2$ and $NaOH$ to convert amides to amines $(A-III)$.$B$. Clemmensen reduction uses $Zn-Hg / HCl$ to redu

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(C) . Hoffmann Bromamide Degradation uses $Br_2$ and $NaOH$ to convert amides to amines $(A-III)$.$B$. Clemmensen reduction uses $Zn-Hg / HCl$ to reduce carbonyl groups to methylene groups $(B-IV)$.$C$. Cannizzaro reaction uses concentrated $KOH$ (or $NaOH$) and heat for aldehydes lacking $\alpha$-hydrogen $(C-I)$.$D$. Reimer-Tiemann reaction uses $CHCl_3$ and $NaOH$ followed by acid workup to introduce a formyl group into phenol $(D-II)$.Therefore,the correct match is $A-III, B-IV, C-I, D-II$.

Class 12 Chemistry 1 Aldehydes, Ketones and Carboxylic Acids: Aldehydes and Ketones Properties

Medium

Match List-$I$ with List-$II$.

List-$I$ Reaction List-$II$ Reagents

$A$. Hoffmann Degradation $I$. Conc. $KOH, \Delta$

$B$. Clemmensen reduction $II$. $CHCl_3, NaOH / H_3O^{+}$

$C$. Cannizzaro reaction $III$. $Br_2, NaOH$

$D$. Reimer-Tiemann reaction $IV$. $Zn-Hg / HCl$

List-$I$ Reaction	List-$II$ Reagents
$A$. Hoffmann Degradation	$I$. Conc. $KOH, \Delta$
$B$. Clemmensen reduction	$II$. $CHCl_3, NaOH / H_3O^{+}$
$C$. Cannizzaro reaction	$III$. $Br_2, NaOH$
$D$. Reimer-Tiemann reaction	$IV$. $Zn-Hg / HCl$