Match List-$I$ with List-$II$.
List-$I$ List-$II$ $A$. Weak intermolecular forces of attraction $I$. Hexamethylenediamine $+$ adipic acid $B$. Hydrogen bonding $II$. $AlEt_3 + TiCl_4$ $C$. Heavily branched polymer $III$. $2-$chloro$-1,3-$butadiene $D$. High density polymer $IV$. Phenol $+$ formaldehyde
Choose the correct answer from the options given below:
| List-$I$ | List-$II$ |
|---|---|
| $A$. Weak intermolecular forces of attraction | $I$. Hexamethylenediamine $+$ adipic acid |
| $B$. Hydrogen bonding | $II$. $AlEt_3 + TiCl_4$ |
| $C$. Heavily branched polymer | $III$. $2-$chloro$-1,3-$butadiene |
| $D$. High density polymer | $IV$. Phenol $+$ formaldehyde |
Choose the correct answer from the options given below:
- A$A-III, B-I, C-IV, D-II$
- B$A-III, B-I, C-II, D-IV$
- C$A-I, B-IV, C-III, D-II$
- D$A-IV, B-I, C-III, D-II$
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Similar Questions
Match List-$I$ with List-$II$.
List-$I$ (Chemicals) List-$II$ (Use / Preparation / Constituent) $(a)$ Alcoholic potassium hydroxide $(i)$ Electrodes in batteries $(b)$ $Pd / BaSO_4$ $(ii)$ Obtained by addition reaction $(c)$ $BHC$ (Benzene hexachloride) $(iii)$ Used for $\beta$-elimination reaction $(d)$ Polyacetylene $(iv)$ Lindlar's catalyst
Choose the most appropriate match.
| List-$I$ (Chemicals) | List-$II$ (Use / Preparation / Constituent) |
|---|---|
| $(a)$ Alcoholic potassium hydroxide | $(i)$ Electrodes in batteries |
| $(b)$ $Pd / BaSO_4$ | $(ii)$ Obtained by addition reaction |
| $(c)$ $BHC$ (Benzene hexachloride) | $(iii)$ Used for $\beta$-elimination reaction |
| $(d)$ Polyacetylene | $(iv)$ Lindlar's catalyst |
Choose the most appropriate match.
Which of the following statements is correct for a spontaneous polymerization reaction?
Match the following:
List-$I$ List-$II$ $A$. $(CH_2-C(Cl)=CH-CH_2)_n$ $I$. Cross-linked network $B$. Nylon-$6,6$ $II$. Elastomer $C$. $HDP$ $III$. Fibre $D$. Melamine-formaldehyde $IV$. Ziegler-Natta catalyst
| List-$I$ | List-$II$ |
|---|---|
| $A$. $(CH_2-C(Cl)=CH-CH_2)_n$ | $I$. Cross-linked network |
| $B$. Nylon-$6,6$ | $II$. Elastomer |
| $C$. $HDP$ | $III$. Fibre |
| $D$. Melamine-formaldehyde | $IV$. Ziegler-Natta catalyst |
Match materials given in Column-$I$ with the polymers given in Column-$II$.
Column-$I$ Column-$II$ $A$. Natural rubber latex $i$. Nylon $B$. Wood laminates $ii$. Neoprene $C$. Ropes and fibres $iii$. Dacron $D$. Polyester fabric $iv$. Melamine formaldehyde resins $E$. Synthetic rubber $v$. Urea-formaldehyde resins $F$. Unbreakable crockery $vi$. cis-polyisoprene
| Column-$I$ | Column-$II$ |
| $A$. Natural rubber latex | $i$. Nylon |
| $B$. Wood laminates | $ii$. Neoprene |
| $C$. Ropes and fibres | $iii$. Dacron |
| $D$. Polyester fabric | $iv$. Melamine formaldehyde resins |
| $E$. Synthetic rubber | $v$. Urea-formaldehyde resins |
| $F$. Unbreakable crockery | $vi$. cis-polyisoprene |
Medium
View SolutionAssertion : $1, 3-$ Butadiene is the monomer for natural rubber.
Reason : Natural rubber is formed through anionic addition polymerization.
Reason : Natural rubber is formed through anionic addition polymerization.
MediumAIIMS 2006
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