Match List-I with the List-II. List-I (R | vedclass

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(D) . $N_{2(g)} + O_{2(g)} \rightarrow 2 NO_{(g)}$ is a combination reaction where two reactants form a single product.$B$. $2 Pb(NO_3)_{2(s)} \righta

Vedclass · Accepted Answer

$A-IV, B-I, C-II, D-III$

Vedclass · Answer

(D) . $N_{2(g)} + O_{2(g)} \rightarrow 2 NO_{(g)}$ is a combination reaction where two reactants form a single product.$B$. $2 Pb(NO_3)_{2(s)} \rightarrow 2 PbO_{(s)} + 4 NO_{2(g)} + O_{2(g)}$ is a decomposition reaction where a single reactant breaks down into multiple products.$C$. $2 Na_{(s)} + 2 H_2 O_{(l)} \rightarrow 2 NaOH_{(aq)} + H_{2(g)}$ is a displacement reaction where $Na$ displaces $H$ from water.$D$. $2 NO_{2(g)} + 2 OH^-_{(aq)} \rightarrow NO^-_{2(aq)} + NO^-_{3(aq)} + H_2 O_{(l)}$ is a disproportionation reaction where the oxidation state of $N$ changes from $+4$ to both $+3$ and $+5$.Therefore,the correct matching is $A-IV, B-I, C-II, D-III$.

List-$I$ (Reaction)	List-$II$ (Type of redox reaction)
$A$. $N_{2(g)} + O_{2(g)} \rightarrow 2 NO_{(g)}$	$I$. Decomposition
$B$. $2 Pb(NO_3)_{2(s)} \rightarrow 2 PbO_{(s)} + 4 NO_{2(g)} + O_{2(g)}$	$II$. Displacement
$C$. $2 Na_{(s)} + 2 H_2 O_{(l)} \rightarrow 2 NaOH_{(aq)} + H_{2(g)}$	$III$. Disproportionation
$D$. $2 NO_{2(g)} + 2 OH^-_{(aq)} \rightarrow NO^-_{2(aq)} + NO^-_{3(aq)} + H_2 O_{(l)}$	$IV$. Combination

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