Match List-I with List-II: List-I (Tetra | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) To determine the electronic configuration in tetrahedral complexes,we first find the oxidation state of the central metal ion:$1$. $TiCl_4$: $Ti$

Vedclass · Accepted Answer

$A-III, B-I, C-IV, D-II$

Vedclass · Answer

(D) To determine the electronic configuration in tetrahedral complexes,we first find the oxidation state of the central metal ion:$1$. $TiCl_4$: $Ti$ is in $+4$ state $(3d^0)$. Configuration: $e^0, t_2^0$ $(III)$.$2$. $[FeO_4]^{2-}$: $Fe$ is in $+6$ state $(3d^2)$. Configuration: $e^2, t_2^0$ $(I)$.$3$. $[FeCl_4]^{-}$: $Fe$ is in $+3$ state $(3d^5)$. Configuration: $e^2, t_2^3$ $(IV)$.$4$. $[CoCl_4]^{2-}$: $Co$ is in $+2$ state $(3d^7)$. Configuration: $e^4, t_2^3$ $(II)$.Thus,the correct matching is $A-III, B-I, C-IV, D-II$.

List-$I$ (Tetrahedral Complex)	List-$II$ (Electronic configuration)
$A$. $TiCl_4$	$I$. $e^2, t_2^0$
$B$. $[FeO_4]^{2-}$	$II$. $e^4, t_2^3$
$C$. $[FeCl_4]^{-}$	$III$. $e^0, t_2^0$
$D$. $[CoCl_4]^{2-}$	$IV$. $e^2, t_2^3$

List-$I$ (Complex/Species)	List-$II$ (Shape and magnetic moment)
$A$. $[Ni(CO)_4]$	$I$. Tetrahedral,$2.8 \ BM$
$B$. $[Ni(CN)_4]^{2-}$	$II$. Square planar,$0 \ BM$
$C$. $[NiCl_4]^{2-}$	$III$. Tetrahedral,$0 \ BM$
$D$. $[MnBr_4]^{2-}$	$IV$. Tetrahedral,$5.9 \ BM$

Similar Questions

An octahedral complex of $Co^{3+}$ is diamagnetic. The hybridisation involved in the formation of the complex is

Which of the following statements is incorrect regarding $[Ni(dmg)_2]$?

The type of hybridization involved in the metal ion of the $[Ni(H_2O)_6]^{2+}$ complex is:

Which of the following pairs of compounds is planar?

Vedclass Test Series

Exam Paper Generator

Online Exam Module