Match List-I with List-II. Choose the correct | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Ozonolysis involves the cleavage of double bonds to form carbonyl compounds. By analyzing the structure of each isomer in List-$I$ and performing

Vedclass · Accepted Answer

$A-III, B-IV, C-I, D-II$

Vedclass · Answer

(B) Ozonolysis involves the cleavage of double bonds to form carbonyl compounds. By analyzing the structure of each isomer in List-$I$ and performing the oxidative cleavage of the double bonds,we can determine the corresponding products in List-$II$. $(A)$ The isomer has two double bonds,which upon ozonolysis yield a dialdehyde with a methyl substituent. This matches product $(III)$. $(B)$ The isomer has two double bonds,which upon ozonolysis yield a keto-aldehyde. This matches product $(IV)$. $(C)$ The isomer has two double bonds,which upon ozonolysis yield a dialdehyde. This matches product $(I)$. $(D)$ The isomer has two double bonds,which upon ozonolysis yield a keto-aldehyde. This matches product $(II)$. Thus,the correct matching is $A-III, B-IV, C-I, D-II$.

Match List-$I$ with List-$II$. Choose the correct answer from the options given below:

Similar Questions

Addition of bromine to $1,3-$butadiene gives

The compounds that will give an isomer of $2,2$-dimethylpropane on catalytic hydrogenation are:
$(1)$ $CH_3-CH=C(CH_3)_2$
$(2)$ $CH_3-CH=CH-CH_3$
$(3)$ $CH_3-CH=CH-CH_2-CH_3$
$(4)$ $CH_3-C(CH_3)=C(CH_3)-CH_3$

What do you mean by olefin? Give an example.

In the reaction $Me-C \equiv C-Et$ $\xrightarrow{Na/liq. NH_3} P$ $\xrightarrow[CCl_4]{Br_2} (Q)$; then $Q$ is

$[CH_3-CH_2-CH(CH_3)-N^{+}(CH_3)_3]OH^{-} \xrightarrow{\text{pyrolysis}}$ major alkene will be

Vedclass Test Series

Exam Paper Generator

Online Exam Module