Match List-I with List-II.List-I (Complex)Lis | vedclass

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(B) . $[CoF_6]^{3-}$: $Co^{3+}$ is $3d^6$. $F^-$ is a weak field ligand,so it forms outer orbital complex with $sp^3d^2$ hybridisation.$B$. $[NiCl_4]^

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$A-III, B-II, C-I, D-IV$

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(B) . $[CoF_6]^{3-}$: $Co^{3+}$ is $3d^6$. $F^-$ is a weak field ligand,so it forms outer orbital complex with $sp^3d^2$ hybridisation.$B$. $[NiCl_4]^{2-}$: $Ni^{2+}$ is $3d^8$. $Cl^-$ is a weak field ligand,so it forms tetrahedral complex with $sp^3$ hybridisation.$C$. $[Co(NH_3)_6]^{3+}$: $Co^{3+}$ is $3d^6$. $NH_3$ is a strong field ligand,so it causes pairing of electrons,forming inner orbital complex with $d^2sp^3$ hybridisation.$D$. $[Ni(CN)_4]^{2-}$: $Ni^{2+}$ is $3d^8$. $CN^-$ is a strong field ligand,so it causes pairing of electrons,forming square planar complex with $dsp^2$ hybridisation.Therefore,the correct matching is $A-III, B-II, C-I, D-IV$.

List-$I$ (Complex)	List-$II$ (Hybridisation of central metal ion)
$A$. $[CoF_6]^{3-}$	$I$. $d^2sp^3$
$B$. $[NiCl_4]^{2-}$	$II$. $sp^3$
$C$. $[Co(NH_3)_6]^{3+}$	$III$. $sp^3d^2$
$D$. $[Ni(CN)_4]^{2-}$	$IV$. $dsp^2$

Match List-$I$ with List-$II$.
List-$I$ (Complex) List-$II$ (Hybridisation of central metal ion)
$A$. $[CoF_6]^{3-}$ $I$. $d^2sp^3$
$B$. $[NiCl_4]^{2-}$ $II$. $sp^3$
$C$. $[Co(NH_3)_6]^{3+}$ $III$. $sp^3d^2$
$D$. $[Ni(CN)_4]^{2-}$ $IV$. $dsp^2$
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Match List-$I$ with List-$II$.List-$I$ (Complex)List-$II$ (Hybridisation of central metal ion)$A$. $[CoF_6]^{3-}$$I$. $d^2sp^3$$B$. $[NiCl_4]^{2-}$$II$. $sp^3$$C$. $[Co(NH_3)_6]^{3+}$$III$. $sp^3d^2$$D$. $[Ni(CN)_4]^{2-}$$IV$. $dsp^2$Choose the correct answer from the options given below: