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(C) The first law of thermodynamics is given by $\Delta Q = \Delta U + \Delta W$,where $\Delta W = P \Delta V$.$(A)$ Isobaric process: Pressure is con

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$(A)-(IV), (B)-(II), (C)-(III), (D)-(I)$

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(C) The first law of thermodynamics is given by $\Delta Q = \Delta U + \Delta W$,where $\Delta W = P \Delta V$.$(A)$ Isobaric process: Pressure is constant $(P = C)$. The work done is $P \Delta V$. Thus,$\Delta Q = \Delta U + P \Delta V$. Matches with $(IV)$.$(B)$ Isochoric process: Volume is constant $(V = C)$,so $\Delta V = 0$ and $\Delta W = 0$. Thus,$\Delta Q = \Delta U$. Matches with $(II)$.$(C)$ Adiabatic process: No heat exchange occurs,so $\Delta Q = 0$. Matches with $(III)$.$(D)$ Isothermal process: Temperature is constant,so internal energy change $\Delta U = 0$. Thus,$\Delta Q = \Delta W$. Matches with $(I)$.Therefore,the correct matching is $(A)-(IV), (B)-(II), (C)-(III), (D)-(I)$.

$A$. Isobaric	$I$. $\Delta Q = \Delta W$
$B$. Isochoric	$II$. $\Delta Q = \Delta U$
$C$. Adiabatic	$III$. $\Delta Q = 0$
$D$. Isothermal	$IV$. $\Delta Q = \Delta U + P \Delta V$

$A$. Steam engine	$I$. Magnetic confinement of plasma
$B$. Electron microscope	$II$. Laws of thermodynamics
$C$. Non-reflecting coatings	$III$. Wave nature of electrons
$D$. Tokamak	$IV$. Interference of light

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