Match List-I with List-II.

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Question

$(A)$. Diethyl amine (secondary amine) and Ethyl amine (primary amine) can be distinguished using the Carbylamine test $(CHCl_3 + KOH, \Delta)$; only

Vedclass · Accepted Answer

$A-II, B-IV, C-III, D-I$

Vedclass · Answer

$(A)$. Diethyl amine (secondary amine) and Ethyl amine (primary amine) can be distinguished using the Carbylamine test $(CHCl_3 + KOH, \Delta)$; only primary amines react to form an isocyanide with a foul smell $(A-II)$.
$B$. Acetaldehyde (aldehyde) and Acetone (ketone) can be distinguished using Tollens' test (Ammonical silver nitrate); only acetaldehyde reacts to form a silver mirror $(B-IV)$.
$C$. Ethanol and Phenol can be distinguished using Neutral $FeCl_3$; phenol gives a characteristic violet color with neutral $FeCl_3$ $(C-III)$.
$D$. Benzoic acid and Cinnamic acid can be distinguished using Bromine water; cinnamic acid contains a carbon-carbon double bond (unsaturation) and decolorizes bromine water, whereas benzoic acid does not $(D-I)$.
Therefore, the correct matching is $A-II, B-IV, C-III, D-I$.

List-$I$ (Mixture of Compounds)	List-$II$ (Reagent used to distinguish)
$A$. Diethyl amine + Ethyl amine	$I$. Bromine water
$B$. Acetaldehyde + Acetone	$II$. $CHCl_3 + KOH, \Delta$
$C$. Ethanol + Phenol	$III$. Neutral $FeCl_3$
$D$. Benzoic acid + Cinnamic acid	$IV$. Ammonical silver nitrate

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