Match List – I with List – II:List - I (Compl | vedclass

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(A) Step $1$: Determine the hybridization and geometry of each complex.Step $2$: $[Co(NH_3)_6]^{3+}$ has $d^2sp^3$ hybridization, which corresponds to

Vedclass · Accepted Answer

$a-ii, b-iii, c-iv, d-i$

Vedclass · Answer

(A) Step $1$: Determine the hybridization and geometry of each complex.Step $2$: $[Co(NH_3)_6]^{3+}$ has $d^2sp^3$ hybridization, which corresponds to an octahedral geometry (ii).Step $3$: $[NiCl_4]^{2-}$ has $sp^3$ hybridization, which corresponds to a tetrahedral geometry (iii).Step $4$: $[Ni(CN)_4]^{2-}$ has $dsp^2$ hybridization, which corresponds to a square planar geometry (iv).Step $5$: $[Fe(CO)_5]$ has $dsp^3$ hybridization, which corresponds to a trigonal bipyramidal geometry $(i)$.Therefore, the correct match is $a-ii, b-iii, c-iv, d-i$.

List - $I$ (Complex)	List – $II$ (Geometry)
$(a)$ $[Co(NH_3)_6]^{3+}$	$(i)$ Trigonal bipyramidal
$(b)$ $[NiCl_4]^{2-}$	(ii) Octahedral
$(c)$ $[Ni(CN)_4]^{2-}$	(iii) Tetrahedral
$(d)$ $[Fe(CO)_5]$	(iv) Square planar

List-$I$	List-$II$
$A. Ni(CO)_4$	$I. sp^3$
$B. [Ni(CN)_4]^{2-}$	$II. sp^3d^2$
$C. [Co(CN)_6]^{3-}$	$III. d^2sp^3$
$D. [CoF_6]^{3-}$	$IV. dsp^2$

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Match List-$I$ with List-$II$.

List-$I$ List-$II$

$A. Ni(CO)_4$ $I. sp^3$

$B. [Ni(CN)_4]^{2-}$ $II. sp^3d^2$

$C. [Co(CN)_6]^{3-}$ $III. d^2sp^3$

$D. [CoF_6]^{3-}$ $IV. dsp^2$

Choose the correct answer from the options given below.

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