Match the LIST-I with LIST-II:

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(A) . Cyclohexanol: It is a secondary alcohol, which is tested by the Lucas test $(ZnCl_2 + conc. HCl)$. Thus, $A-III$.
$B$. Cyclohexylamine: It is a

Vedclass · Accepted Answer

$A-III, B-I, C-IV, D-II$

Vedclass · Answer

(A) . Cyclohexanol: It is a secondary alcohol, which is tested by the Lucas test $(ZnCl_2 + conc. HCl)$. Thus, $A-III$.
$B$. Cyclohexylamine: It is a primary amine, which is tested by Hinsberg's reagent $(Benzenesulfonyl chloride)$. Thus, $B-I$.
$C$. Cyclohexanecarbaldehyde: It is an aldehyde, which is tested by Tollen's test $(Ammoniacal silver nitrate)$. Thus, $C-IV$.
$D$. Phenol: It is tested by the Phthalein dye test (reaction with phthalic anhydride in the presence of conc. $H_2SO_4$). Thus, $D-II$.
Therefore, the correct matching is $A-III, B-I, C-IV, D-II$.

$LIST$-$I$	$LIST$-$II$
$A$. Cyclohexanol	$I$. Hinsberg's reagent
$B$. Cyclohexylamine	$II$. Phthalein dye test
$C$. Cyclohexanecarbaldehyde	$III$. Lucas test
$D$. Phenol	$IV$. Tollen's test

Match the $LIST$-$I$ with $LIST$-$II$:

$LIST$-$I$ $LIST$-$II$

$A$. Cyclohexanol $I$. Hinsberg's reagent

$B$. Cyclohexylamine $II$. Phthalein dye test

$C$. Cyclohexanecarbaldehyde $III$. Lucas test

$D$. Phenol $IV$. Tollen's test

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Match the $LIST$-$I$ with $LIST$-$II$: $LIST$-$I$ $LIST$-$II$ $A$. Cyclohexanol $I$. Hinsberg's reagent $B$. Cyclohexylamine $II$. Phthalein dye test $C$. Cyclohexanecarbaldehyde $III$. Lucas test $D$. Phenol $IV$. Tollen's test