Match the column-I with column-II A. S rig | vedclass

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(C) $1$. $S \rightarrow S^{-}$: Addition of an electron to $S$ releases energy (exothermic,$Q$) and results in a stable configuration. $2$. $N^{-} \ri

Vedclass · Accepted Answer

$A$ $\rightarrow Q, B$ $\rightarrow Q, S, C$ $\rightarrow P, R, D$ $\rightarrow Q$

Vedclass · Answer

(C) $1$. $S \rightarrow S^{-}$: Addition of an electron to $S$ releases energy (exothermic,$Q$) and results in a stable configuration. $2$. $N^{-} \rightarrow N$: Removal of an electron from $N^{-}$ $(2p^4)$ to form $N$ $(2p^3)$ is exothermic $(Q)$ and results in a half-filled stable configuration $(S)$. $3$. $O^{-} \rightarrow O^{2-}$: Addition of an electron to $O^{-}$ is endothermic $(P)$ due to inter-electronic repulsion,and $O^{2-}$ achieves a stable inert gas configuration $(R)$. $4$. $P \rightarrow P^{-}$: Addition of an electron to $P$ $(3p^3)$ is exothermic $(Q)$ as it moves towards a more stable state,but does not reach inert gas or half-filled configurations. Thus,the correct match is $A$ $\rightarrow Q, B$ $\rightarrow Q, S, C$ $\rightarrow P, R, D$ $\rightarrow Q$.

$A. S \rightarrow S^{-}$	$P. \text{Endothermic process}$
$B. N^{-} \rightarrow N$	$Q. \text{Exothermic process}$
$C. O^{-} \rightarrow O^{2-}$	$R. \text{Inert gas configuration in product}$
$D. P \rightarrow P^{-}$	$S. \text{Half filled configuration in product}$

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