Match the electronic configurations in List-I | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The electronic configurations are determined based on the crystal field splitting of the metal ions:$1$. $[Fe(H_2O)_6]^{2+}$: $Fe^{2+}$ is $3d^6$.

Vedclass · Accepted Answer

$P$ $\rightarrow 3; Q$ $\rightarrow 2; R$ $\rightarrow 4; S$ $\rightarrow 1$

Vedclass · Answer

(A) The electronic configurations are determined based on the crystal field splitting of the metal ions:$1$. $[Fe(H_2O)_6]^{2+}$: $Fe^{2+}$ is $3d^6$. $H_2O$ is a weak field ligand $(WFL)$,so the configuration is $t_{2g}^4 e_g^2$ $(S \rightarrow 1)$.$2$. $[Mn(H_2O)_6]^{2+}$: $Mn^{2+}$ is $3d^5$. $H_2O$ is a $WFL$,so the configuration is $t_{2g}^3 e_g^2$ $(Q \rightarrow 2)$.$3$. $[Co(NH_3)_6]^{3+}$: $Co^{3+}$ is $3d^6$. $NH_3$ is a strong field ligand $(SFL)$,so the configuration is $t_{2g}^6 e_g^0$ $(P \rightarrow 3)$.$4$. $[FeCl_4]^{-}$: $Fe^{3+}$ is $3d^5$. It is a tetrahedral complex with a $WFL$,so the configuration is $e^2 t_2^3$ $(R \rightarrow 4)$.$5$. $[CoCl_4]^{2-}$: $Co^{2+}$ is $3d^7$. It is a tetrahedral complex with a $WFL$,so the configuration is $e^4 t_2^3$.Thus,the correct matching is $P$ $\rightarrow 3, Q$ $\rightarrow 2, R$ $\rightarrow 4, S$ $\rightarrow 1$.

List-$I$	List-$II$
$P$. $t_{2g}^6 e_g^0$	$1$. $[Fe(H_2O)_6]^{2+}$
$Q$. $t_{2g}^3 e_g^2$	$2$. $[Mn(H_2O)_6]^{2+}$
$R$. $e^2 t_2^3$	$3$. $[Co(NH_3)_6]^{3+}$
$S$. $t_{2g}^4 e_g^2$	$4$. $[FeCl_4]^{-}$
	$5$. $[CoCl_4]^{2-}$

Similar Questions

According to crystal field theory,the $M-L$ bond in a complex is

In which of the following coordination entities the magnitude of $\Delta_o$ ($CFSE$ in octahedral field) will be maximum? (Atomic Number of $Co = 27$)

Which of the following ion configurations has zero $CFSE$ in both strong and weak field ligands in an octahedral complex?

In which of the following complexes will the $CFSE$ (Crystal Field Stabilization Energy),$\Delta_0$ be equal to zero?

Write down the number of $3d$ electrons in each of the following ions:
$Ti^{2+}, V^{2+}, Cr^{3+}, Mn^{2+}, Fe^{2+}, Fe^{3+}, Co^{2+}, Ni^{2+}$ and $Cu^{2+}$
Indicate how you would expect the five $3d$ orbitals to be occupied for these hydrated ions (octahedral).

Vedclass Test Series

Exam Paper Generator

Online Exam Module