Match the following ( f is number of degrees | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The ratio of specific heats is given by $\gamma = \frac{C_P}{C_V} = 1 + \frac{2}{f}$.
For Monoatomic gas: $f=3$,so $\gamma = 1 + \frac{2}{3} = \f

Vedclass · Accepted Answer

$A-II, B-III, C-IV, D-I$

Vedclass · Answer

(A) The ratio of specific heats is given by $\gamma = \frac{C_P}{C_V} = 1 + \frac{2}{f}$.
For Monoatomic gas: $f=3$,so $\gamma = 1 + \frac{2}{3} = \frac{5}{3}$. Thus,$A-II$.
For Diatomic (rigid) gas: $f=5$,so $\gamma = 1 + \frac{2}{5} = \frac{7}{5}$. Thus,$B-III$.
For Diatomic (non-rigid) gas: $f=7$,so $\gamma = 1 + \frac{2}{7} = \frac{9}{7}$. Thus,$C-IV$.
For Polyatomic gas: The general formula for $\gamma$ is $\frac{4+f}{3+f}$. Thus,$D-I$.
Therefore,the correct matching is $A-II, B-III, C-IV, D-I$.

	Gases		$C_P/C_V$ value
$A$	Monoatomic	$I$	$(4+f)/(3+f)$
$B$	Diatomic (rigid)	$II$	$5/3$
$C$	Diatomic (non-rigid)	$III$	$7/5$
$D$	Polyatomic	$IV$	$9/7$

Match the following ( $f$ is number of degrees of freedom):

Gases $C_P/C_V$ value

$A$ Monoatomic $I$ $(4+f)/(3+f)$

$B$ Diatomic (rigid) $II$ $5/3$

$C$ Diatomic (non-rigid) $III$ $7/5$

$D$ Polyatomic $IV$ $9/7$

Similar Questions

For a gas,$\frac{R}{C_{v}} = 0.67$. This gas is made up of molecules which are

The quantity of heat required to raise the temperature of one mole of a monoatomic gas by one degree Kelvin at constant volume is

The ratio of specific heats $(\gamma)$ of an ideal gas is given by

The molar specific heat at constant pressure for a monoatomic gas is

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Match the following ( $f$ is number of degrees of freedom): Gases $C_P/C_V$ value $A$ Monoatomic $I$ $(4+f)/(3+f)$ $B$ Diatomic (rigid) $II$ $5/3$ $C$ Diatomic (non-rigid) $III$ $7/5$ $D$ Polyatomic $IV$ $9/7$