Match the following and find the correct pairs.
List-$I$List-$II$
$(A)$ Fleming's left hand rule$(i)$ Direction of induced current
$(B)$ Right hand thumb rule(ii) Magnitude and direction of magnetic induction
$(C)$ Biot-Savart law(iii) Direction of force due to magnetic induction
$(D)$ Fleming's right hand rule(iv) Direction of magnetic lines due to current

  • A
    $(A)-(iii), (B)-(i), (C)-(ii), (D)-(iv)$
  • B
    $(A)-(iii), (B)-(iv), (C)-(ii), (D)-(i)$
  • C
    $(A)-(ii), (B)-(iv), (C)-(iii), (D)-(i)$
  • D
    $(A)-(iv), (B)-(iii), (C)-(i), (D)-(ii)$

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Similar Questions

In the following hexagons,made up of two different materials $P$ and $Q$,current enters and leaves from points $X$ and $Y$ respectively. In which case is the magnetic field at its centre not zero?

The dimensional formula of $\frac{1}{2} \mu_0 H^2$ (where $\mu_0$ is the permeability of free space and $H$ is the magnetic field intensity) is:

$A$ charged particle (electron or proton) is introduced at the origin $(x=0, y=0, z=0)$ with a given initial velocity $\overrightarrow{v}$. $A$ uniform electric field $\overrightarrow{E}$ and magnetic field $\vec{B}$ are given in columns $I, II$ and $III$, respectively. The quantities $E_0, B_0$ are positive in magnitude.
Column $I$Column $II$Column $III$
$(I)$ Electron with $\overrightarrow{v}=2 \frac{E_0}{B_0} \hat{x}$$(i)$ $\overrightarrow{E}=E_0 \hat{z}$$(P)$ $\overrightarrow{B}=-B_0 \hat{x}$
$(II)$ Electron with $\overrightarrow{v}=\frac{E_0}{B_0} \hat{y}$$(ii)$ $\overrightarrow{E}=-E_0 \hat{y}$$(Q)$ $\overrightarrow{B}=B_0 \hat{x}$
$(III)$ Proton with $\overrightarrow{v}=0$$(iii)$ $\overrightarrow{E}=-E_0 \hat{x}$$(R)$ $\overrightarrow{B}=B_0 \hat{y}$
$(IV)$ Proton with $\overrightarrow{v}=2 \frac{E_0}{B_0} \hat{x}$$(iv)$ $\overrightarrow{E}=E_0 \hat{x}$$(S)$ $\overrightarrow{B}=B_0 \hat{z}$

$(1)$ In which case will the particle move in a straight line with constant velocity?
$(2)$ In which case will the particle describe a helical path with axis along the positive $z$ direction?
$(3)$ In which case would the particle move in a straight line along the negative direction of $y$-axis (i.e., move along $-\hat{y}$)?

$A$ charge $Q$ is uniformly distributed over the surface of a nonconducting disc of radius $R$. The disc rotates about an axis perpendicular to its plane and passing through its centre with an angular velocity $\omega$. As a result of this rotation,a magnetic field of induction $B$ is obtained at the centre of the disc. If we keep both the amount of charge placed on the disc and its angular velocity constant and vary the radius of the disc,then the variation of the magnetic induction at the centre of the disc will be represented by which of the following figures?

Match List-$I$ with List-$II$.
List-$I$List-$II$
$(A)$ Permeability of free space$(I) \ [M L^2 T^{-2}]$
$(B)$ Magnetic field$(II) \ [M T^{-2} A^{-1}]$
$(C)$ Magnetic moment$(III) \ [M L T^{-2} A^{-2}]$
$(D)$ Torsional constant$(IV) \ [L^2 A]$

Choose the correct answer from the options given below:

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