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(A) The correct matches are as follows:$A$. $H_3BO_3$ (Boric acid) exhibits intermolecular hydrogen bonding in its solid state. Thus, $A-3$.$B$. $AlCl

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$A-3, B-1, C-4, D-2$

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(A) The correct matches are as follows:$A$. $H_3BO_3$ (Boric acid) exhibits intermolecular hydrogen bonding in its solid state. Thus, $A-3$.$B$. $AlCl_3$ exists as a dimer $(Al_2Cl_6)$ in the vapor phase or non-polar solvents. Thus, $B-1$.$C$. $B_3N_3H_6$ (Borazine) is known as inorganic benzene due to its structural similarity to benzene. Thus, $C-4$.$D$. $BF_3$ involves back bonding between the lone pair of fluorine and the vacant p-orbital of boron. Thus, $D-2$.Therefore, the correct sequence is $A-3, B-1, C-4, D-2$.

List-$I$ (Compound)	List-$II$ (Property/Name/Structure)
$A$. $H_3BO_3$	$1$. Dimeric form
$B$. $AlCl_3$	$2$. Back bonding
$C$. $B_3N_3H_6$	$3$. Hydrogen bonding
$D$. $BF_3$	$4$. Inorganic benzene

Match the following compounds in List-$I$ with their properties/names in List-$II$.
List-$I$ (Compound) List-$II$ (Property/Name/Structure)
$A$. $H_3BO_3$ $1$. Dimeric form
$B$. $AlCl_3$ $2$. Back bonding
$C$. $B_3N_3H_6$ $3$. Hydrogen bonding
$D$. $BF_3$ $4$. Inorganic benzene

Similar Questions

$A$ and $B$ are formed when borax is dissolved in water. $C$ and $B$ are formed when borax is reacted with aqueous $HCl$ solution. What are $A$ and $C$ respectively?

Chemically,borax is:

Which of the following properties does not support the anomalous behavior of $Boron$?

Boric acid is an acid because its molecule

Assertion : Boron is a metalloid.
Reason : Boron shows metallic nature.

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Match the following compounds in List-$I$ with their properties/names in List-$II$.List-$I$ (Compound)List-$II$ (Property/Name/Structure)$A$. $H_3BO_3$$1$. Dimeric form$B$. $AlCl_3$$2$. Back bonding$C$. $B_3N_3H_6$$3$. Hydrogen bonding$D$. $BF_3$$4$. Inorganic benzene