Easy
Match the following List-$I$ (Method) with List-$II$ (Metal refined):
List-$I$ (Method) List-$II$ (Metal refined) $(A)$ Zone refining $(I)$ $Sn$ $(B)$ Liquation $(II)$ $In$ $(C)$ Vapour phase refining $(III)$ $Zn$ $(D)$ Distillation $(IV)$ $Zr$ - $(V)$ $Al$
The correct answer is:
| List-$I$ (Method) | List-$II$ (Metal refined) |
|---|---|
| $(A)$ Zone refining | $(I)$ $Sn$ |
| $(B)$ Liquation | $(II)$ $In$ |
| $(C)$ Vapour phase refining | $(III)$ $Zn$ |
| $(D)$ Distillation | $(IV)$ $Zr$ |
| - | $(V)$ $Al$ |
The correct answer is:
- A$A-IV, B-I, C-III, D-V$
- B$A-II, B-I, C-IV, D-III$
- C$A-II, B-V, C-III, D-I$
- D$A-I, B-III, C-IV, D-II$
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Similar Questions
In the extraction of nickel by the Mond process,the metal is obtained by:
Easy
View SolutionMatch the refining methods (Column $I$) with metals (Column $II$).
Column $I$ (Refining methods) Column $II$ (Metals) $(I)$ Liquation $(a)$ $Zr$ $(II)$ Zone refining $(b)$ $Ni$ $(III)$ Mond process $(c)$ $Sn$ $(IV)$ Van Arkel Method $(d)$ $Ga$
| Column $I$ (Refining methods) | Column $II$ (Metals) |
| $(I)$ Liquation | $(a)$ $Zr$ |
| $(II)$ Zone refining | $(b)$ $Ni$ |
| $(III)$ Mond process | $(c)$ $Sn$ |
| $(IV)$ Van Arkel Method | $(d)$ $Ga$ |
DifficultJEE MAIN 2019
View SolutionMatch the List-$I$ and List-$II$.
List-$I$ List-$II$ $A$. Van Arkel method $P$. Purification of titanium $B$. Solvay process $Q$. Manufacture of $Na_2CO_3$ $C$. Bessemerisation $R$. Reduction of copper $D$. Hall-$H$éroult process $S$. Extraction of aluminium
| List-$I$ | List-$II$ |
|---|---|
| $A$. Van Arkel method | $P$. Purification of titanium |
| $B$. Solvay process | $Q$. Manufacture of $Na_2CO_3$ |
| $C$. Bessemerisation | $R$. Reduction of copper |
| $D$. Hall-$H$éroult process | $S$. Extraction of aluminium |
Medium
View SolutionWhich of the following is the correct match?
Difficult
View SolutionWhat is blister copper?
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