Match the following List-$I$ (Acid) with List-$II$ (Reagents used for preparation):
| List-$I$ (Acid) | List-$II$ (Reagents used for preparation) |
| :--- | :--- |
| $A. H_3PO_2$ | $I. \text{Red } P_4 \text{alkali}$ |
| $B. H_4P_2O_5$ | $II. \text{White } P_4 \text{alkali}$ |
| $C. H_3PO_4$ | $III. PCl_3; H_3PO_3$ |
| $D. H_4P_2O_7$ | $IV. P_2O_5; H_2O$ |
| | $V. H_3PO_4; \Delta$ |

  • A
    $A-II, B-III, C-IV, D-V$
  • B
    $A-I, B-III, C-IV, D-V$
  • C
    $A-II, B-III, C-V, D-IV$
  • D
    $A-I, B-II, C-III, D-IV$

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Similar Questions

Given below are two statements :
Statement $-I :$ The pentavalent oxide of group $-15$ element,$E_2O_5$,is less acidic than trivalent oxide,$E_2O_3$,of the same element.
Statement $-II :$ The acidic character of trivalent oxide of group $15$ elements,$E_2O_3$,decreases down the group.
In light of the above statements,choose the most appropriate answer from the options given below.

Ionic radius (in $\mathring{A}$) of $As^{3+}$,$Sb^{3+}$ and $Bi^{3+}$ follow the order:

Which of the following compounds gives $N_2$ on heating?

Which one of the following cannot form an amphoteric oxide?

Match List $I$ with List $II$:
List $I$ Oxide List $II$ Type of Bond
$A. N_2O_4$ $I. 1 N-O$ bond
$B. NO_2$ $II. 1 N-O-N$ bond
$C. N_2O_5$ $III. 1 N-N$ bond
$D. N_2O$ $IV. 1 N=N / N\equiv N$ bond

Choose the correct answer from the options given below:

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