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(A) The colours of the halogens are as follows:$F_2$ is pale yellow.$Cl_2$ is greenish yellow.$Br_2$ is reddish brown (often simplified to red in some

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$A-III, B-IV, C-I, D-II$

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(A) The colours of the halogens are as follows:$F_2$ is pale yellow.$Cl_2$ is greenish yellow.$Br_2$ is reddish brown (often simplified to red in some contexts).$I_2$ is violet.Matching these with the given options:$A(F_2) - III$ (Yellow)$B(Cl_2) - IV$ (Greenish yellow)$C(Br_2) - I$ (Red)$D(I_2) - II$ (Violet)Therefore, the correct sequence is $A-III, B-IV, C-I, D-II$.

$A$. $F_2$	$I$. Red
$B$. $Cl_2$	$II$. Violet
$C$. $Br_2$	$III$. Yellow
$D$. $I_2$	$IV$. Greenish yellow

Match the following molecules with their respective colours:
$A$. $F_2$ $I$. Red
$B$. $Cl_2$ $II$. Violet
$C$. $Br_2$ $III$. Yellow
$D$. $I_2$ $IV$. Greenish yellow

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Match the following molecules with their respective colours:$A$. $F_2$$I$. Red$B$. $Cl_2$$II$. Violet$C$. $Br_2$$III$. Yellow$D$. $I_2$$IV$. Greenish yellow