Match the following reactions in Column-$1$ with their main products in Column-$2$.
Column-$1$ (Reaction) Column-$2$ (Main product) $A$. $B_2H_6 + 2CO \longrightarrow$ $I$. $B_2O_3$ $B$. $B_2H_6 + 3O_2 \longrightarrow$ $II$. $2BH_3 \cdot CO$ $C$. $B_2H_6 + 6H_2O \longrightarrow$ $III$. $2H_3BO_3$
The correct match is:
| Column-$1$ (Reaction) | Column-$2$ (Main product) |
|---|---|
| $A$. $B_2H_6 + 2CO \longrightarrow$ | $I$. $B_2O_3$ |
| $B$. $B_2H_6 + 3O_2 \longrightarrow$ | $II$. $2BH_3 \cdot CO$ |
| $C$. $B_2H_6 + 6H_2O \longrightarrow$ | $III$. $2H_3BO_3$ |
The correct match is:
- A$A-IV, B-I, C-III$
- B$A-II, B-III, C-V$
- C$A-IV, B-III, C-I$
- D$A-II, B-I, C-III$
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Similar Questions
Three pairs of compounds are given below. Identify the compound in each pair which has the group $13$ element in a more stable oxidation state. Give reasons for your choice and state the nature of bonding. $(A)$ $TlCl_3, TlCl$ $(B)$ $AlCl_3, AlCl$ $(C)$ $InCl_3, InCl$
Difficult
View SolutionWhich of the following statements is true about $H_3BO_3$?
Easy
View SolutionGiven below are two statements:
Statement $I$: Aluminium is more electropositive than thallium as the standard electrode potential value of $E^\circ_{Al^{3+}/Al}$ is negative and $E^\circ_{Tl^{3+}/Tl}$ is positive.
Statement $II$: The sum of first three ionization enthalpies of boron is very high when compared to that of aluminium. Due to this reason, boron forms covalent compounds only and aluminium forms $Al^{3+}$ ion.
Statement $I$: Aluminium is more electropositive than thallium as the standard electrode potential value of $E^\circ_{Al^{3+}/Al}$ is negative and $E^\circ_{Tl^{3+}/Tl}$ is positive.
Statement $II$: The sum of first three ionization enthalpies of boron is very high when compared to that of aluminium. Due to this reason, boron forms covalent compounds only and aluminium forms $Al^{3+}$ ion.
Which one of the following is correct relating to diborane $(B_2H_6)$?
Explain the nature of boric acid $(H_3BO_3)$ as a Lewis acid in water. The structure of $H_3BO_3$ is given below:
$H-O-B(OH)_2$
$H-O-B(OH)_2$
Medium
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