Match the following:
List-$I$ (Transition metal,$M$) List-$II$ ($E_{M^{2+}/ M}^{\ominus}$ in $V$) $A$. $Ni$ $I$. $-1.18$ $B$. $Mn$ $II$. $-0.91$ $C$. $Fe$ $III$. $-0.25$ $D$. $Cr$ $IV$. $-0.44$
The correct answer is
| List-$I$ (Transition metal,$M$) | List-$II$ ($E_{M^{2+}/ M}^{\ominus}$ in $V$) |
| $A$. $Ni$ | $I$. $-1.18$ |
| $B$. $Mn$ | $II$. $-0.91$ |
| $C$. $Fe$ | $III$. $-0.25$ |
| $D$. $Cr$ | $IV$. $-0.44$ |
The correct answer is
- A$A-III, B-I, C-IV, D-II$
- B$A-III, B-IV, C-I, D-II$
- C$A-III, B-I, C-IV, D-II$
- D$A-I, B-IV, C-II, D-III$
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The correct order of $E^o$ $M^{2+}/M$ values with negative sign for the four successive elements $Cr$,$Mn$,$Fe$ and $Co$ is
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column-$II$ $(\text{Metal})$
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| $ii$. $3d$ series element that can show upto $+7$ oxidation state | $b$. $Cr$ |
| $iii$. $3d$ series element with highest melting point | $c$. $Os$ |
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