Match the following: I. Zn^{2+}(i) d^8 tex | vedclass

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(B) The correct match is $I 	o (ii), II 	o (iii), III 	o (i)$.- $Zn^{2+} (Z=30)$: The electronic configuration is $[Ar] 3d^{10}$. Since all $d$-orb

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$I 	o (ii), II 	o (iii), III 	o (i)$

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(B) The correct match is $I 	o (ii), II 	o (iii), III 	o (i)$.- $Zn^{2+} (Z=30)$: The electronic configuration is $[Ar] 3d^{10}$. Since all $d$-orbitals are fully filled,there are no unpaired electrons,making it colourless.- $Cu^{2+} (Z=29)$: The electronic configuration is $[Ar] 3d^9$. It has one unpaired electron. The magnetic moment is $\mu = \sqrt{n(n+2)} = \sqrt{1(1+2)} = \sqrt{3} \approx 1.73 \ 	ext{BM}$.- $Ni^{2+} (Z=28)$: The electronic configuration is $[Ar] 3d^8$. Thus,it has a $d^8$ configuration.

$I. \ Zn^{2+}$	$(i) \ d^8 \ \text{configuration}$
$II. \ Cu^{2+}$	$(ii) \ \text{Colourless}$
$III. \ Ni^{2+}$	$(iii) \ \mu = 1.73 \ \text{BM}$

Match the following:
$I. \ Zn^{2+}$ $(i) \ d^8 \ \text{configuration}$
$II. \ Cu^{2+}$ $(ii) \ \text{Colourless}$
$III. \ Ni^{2+}$ $(iii) \ \mu = 1.73 \ \text{BM}$

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Match the following: $I. \ Zn^{2+}$$(i) \ d^8 \ \text{configuration}$$II. \ Cu^{2+}$$(ii) \ \text{Colourless}$$III. \ Ni^{2+}$$(iii) \ \mu = 1.73 \ \text{BM}$