Match the following: A. Acetaldehyde,vinyl al | vedclass

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(B) The correct matches are as follows: $A$. Acetaldehyde $(CH_3CHO)$ and vinyl alcohol $(CH_2=CH-OH)$ are tautomers. $B$. Eclipsed and staggered etha

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$A-2, B-4, C-1, D-5$

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(B) The correct matches are as follows: $A$. Acetaldehyde $(CH_3CHO)$ and vinyl alcohol $(CH_2=CH-OH)$ are tautomers. $B$. Eclipsed and staggered ethane are two conformations of ethane,hence they are conformational isomers. $C$. $(+)2$-butanol and $(-)2$-butanol are non-superimposable mirror images of each other,hence they are enantiomers. $D$. Methyl-$n$-propylamine $(CH_3-NH-CH_2CH_2CH_3)$ and diethylamine $((C_2H_5)_2NH)$ have different alkyl groups attached to the same functional group $(-NH-)$,hence they are metamers. Therefore,the correct matching is $A-2, B-4, C-1, D-5$.

$A$. Acetaldehyde,vinyl alcohol	$1$. Enantiomers
$B$. Eclipsed and staggered ethane	$2$. Tautomers
$C$. $(+)2$-butanol,$(-)2$-butanol	$3$. Chain isomers
$D$. Methyl-$n$-propylamine and diethylamine	$4$. Conformational isomers
	$5$. Metamers

Match the following:
$A$. Acetaldehyde,vinyl alcohol $1$. Enantiomers
$B$. Eclipsed and staggered ethane $2$. Tautomers
$C$. $(+)2$-butanol,$(-)2$-butanol $3$. Chain isomers
$D$. Methyl-$n$-propylamine and diethylamine $4$. Conformational isomers
$5$. Metamers

Similar Questions

The stable form of $trans-1,4-$dimethylcyclohexane is represented as:

The product of the reaction is:

$(i)$ Number of geometrical isomers for the given structure $X$ (assuming $X$ contains $3$ stereogenic double bonds):
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$(iii)$ Number of ethers with molecular formula $C_4H_{10}O = Z$
Find the value of $X + Y + Z$.

The compound $CHCl=CHCHOHCOOH$ with molecular formula $C_4H_5O_3Cl$ can exhibit:

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Match the following: $A$. Acetaldehyde,vinyl alcohol$1$. Enantiomers$B$. Eclipsed and staggered ethane$2$. Tautomers$C$. $(+)2$-butanol,$(-)2$-butanol$3$. Chain isomers$D$. Methyl-$n$-propylamine and diethylamine$4$. Conformational isomers$5$. Metamers