Match the following: List-I (Glycosidic linka | vedclass

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(D) . Amylose is a linear polymer of $\alpha-D-glucose$ units linked by $\alpha-1,4$-glycosidic bonds. Thus,$A-I$.$B$. Cellulose is a linear polymer o

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$A-I, B-III, C-II$

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(D) . Amylose is a linear polymer of $\alpha-D-glucose$ units linked by $\alpha-1,4$-glycosidic bonds. Thus,$A-I$.$B$. Cellulose is a linear polymer of $\beta-D-glucose$ units linked by $\beta-1,4$-glycosidic bonds. Thus,$B-III$.$C$. Amylopectin is a branched polymer of $\alpha-D-glucose$ units with $\alpha-1,4$-glycosidic bonds in the chain and $\alpha-1,6$-glycosidic bonds at the branching points. Thus,$C-II$.Therefore,the correct matching is $A-I, B-III, C-II$.

List-$I$ (Glycosidic linkage)	List-$II$ (Polysaccharide)
$A$. $\alpha-1,4$	$I$. Amylose
$B$. $\beta-1,4$	$II$. Cellulose
$C$. $\alpha-1,4, \alpha-1,6$	$III$. Amylopectin

Match the following:
List-$I$ (Glycosidic linkage) List-$II$ (Polysaccharide)
$A$. $\alpha-1,4$ $I$. Amylose
$B$. $\beta-1,4$ $II$. Cellulose
$C$. $\alpha-1,4, \alpha-1,6$ $III$. Amylopectin

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Match the following: List-$I$ (Glycosidic linkage)List-$II$ (Polysaccharide)$A$. $\alpha-1,4$$I$. Amylose$B$. $\beta-1,4$$II$. Cellulose$C$. $\alpha-1,4, \alpha-1,6$$III$. Amylopectin