Match the isotopes in List I with the number | vedclass

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(B) The number of neutrons $n$ is calculated as $n = A - Z$, where $A$ is the mass number and $Z$ is the atomic number.$(A)$ $^{24}_{12}Mg$: $n = 24 -

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$(A)$-$(II)$, $(B)$-$(IV)$, $(C)$-$(I)$, $(D)$-$(III)$

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(B) The number of neutrons $n$ is calculated as $n = A - Z$, where $A$ is the mass number and $Z$ is the atomic number.$(A)$ $^{24}_{12}Mg$: $n = 24 - 12 = 12$ (Matches $II$).$(B)$ $^{27}_{13}Al$: $n = 27 - 13 = 14$ (Matches $IV$).$(C)$ $^{9}_{4}Be$: $n = 9 - 4 = 5$ (Matches $I$).$(D)$ $^{12}_{6}C$: $n = 12 - 6 = 6$ (Matches $III$).Therefore, the correct matching is $(A)$-$(II)$, $(B)$-$(IV)$, $(C)$-$(I)$, $(D)$-$(III)$.

$(A)$. $^{24}_{12}Mg$	$(I)$. $5$
$(B)$. $^{27}_{13}Al$	$(II)$. $12$
$(C)$. $^{9}_{4}Be$	$(III)$. $6$
$(D)$. $^{12}_{6}C$	$(IV)$. $14$

Match the isotopes in List $I$ with the number of neutrons in List $II$.
$(A)$. $^{24}_{12}Mg$ $(I)$. $5$
$(B)$. $^{27}_{13}Al$ $(II)$. $12$
$(C)$. $^{9}_{4}Be$ $(III)$. $6$
$(D)$. $^{12}_{6}C$ $(IV)$. $14$

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Match the isotopes in List $I$ with the number of neutrons in List $II$.$(A)$. $^{24}_{12}Mg$$(I)$. $5$$(B)$. $^{27}_{13}Al$$(II)$. $12$$(C)$. $^{9}_{4}Be$$(III)$. $6$$(D)$. $^{12}_{6}C$$(IV)$. $14$